std::move对堆栈变量有意义吗

我需要创建一个大小为 1024 的结构列表。所以我试图通过使用移动语义来优化推送操作到列表中。但是移动语义仅对堆分配的内存有意义（据我所知）。有人可以建议我这样做的更好方法。这是我的代码

#include <iostream>
#include <list>
    
struct St {
    int32_t arr[1024];
};
    
int main() {
    std::list<St> struct_list;
    for(int32_t i = 0; i < 1024; ++i) {
        St st; // stack allocated and memory gets deallocated after each loop
        std::cout << &st << std::endl;
        struct_list.emplace_back(std::move(st)); // I feel std::move doesn't make any sense here even if I implement move constructor, still data gets copied into the std::list which is allocated in heap, so not efficient.
        std::cout << &struct_list.back() << "n" << std::endl;
    }
        
    return EXIT_SUCCESS;
}

回答

struct St {
    int32_t arr[1024];
};

struct St {
    std::vector<int32_t> vec;
};